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18x^2+75x+63=0
a = 18; b = 75; c = +63;
Δ = b2-4ac
Δ = 752-4·18·63
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-33}{2*18}=\frac{-108}{36} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+33}{2*18}=\frac{-42}{36} =-1+1/6 $
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